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6.3072 g >>molarity = moles of solute/volume of solution (in litres) 0.45 m = n/0.4 l n = 0.45 m × 0.4 l = 0.18 mol you need 0.18 mol of nh_4oh molar mass of nh_4oh is 35.04 g/mol mass of solute = 0.18 cancelmol × 35.04 g/cancelmol = 6.3072 g Nickel (ii)hydroxide may be formed without or (more likely. < since the molarity of either acid is the same, the moles of each acid are equal

That means the difference between their ph is determined solely on which acid dissociates more 60ml ⋅ 0.45m ol/l = 27mm ol of n aoh (dont forget the m for milli=one thousandth) this will produce 27 2 = 13.5mm ol of n i(oh)2 now you multiply this by the molecular mass number to get the weight in milligrams (divide by 1000 to get the grams) Since the strong acid dissociates more (releases more #h^+# ions), it will have a lower ph

= since both acids are monoprotic (they only release one hydrogen) they will both take the same amount of #oh.

When an acid and a base are placed together, they react to neutralize the acid and base properties, producing a salt (neutralisation) The compound formed by the cation of the base and the anion of the acid is called a salt Example h cl + n aoh → n acl + h 2o hydrochloric acid + sodium hydroxide →. Copper forms an insoluble hydroxide that is fairly poorly characterized

Another way we could look it as a hydrated copper oxide, i.e Cuo ⋅ oh 2 ≡ cu(oh)2. Here's how you could do that You can prepare phenylmethanol, c_6h_5ch_2oh, by reacting phenylmagnesium bromide, c_6h_5mgbr, with formaldehyde, ch_2o

You can think about this reaction as being an alkylation reaction.

So this is a propanol derivative Likewise, 2 moles of lithium produces 2. Because n aoh → n a+ + oh − and n i2+ + 2oh −→n i(oh)2 total mols of n aoh

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